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Ratio and Proportion Concepts
QUANTITATIVEAPTITUDE

Ratio and Proportion Concepts

Learn ratio, proportion, variation, scaling, and comparison techniques used in aptitude problems.

1. Income, Expenditure & Savings

  • Formula:
Savings=IncomeExpenditure \text{Savings}=\text{Income}-\text{Expenditure}

If income and expenditure are given in ratios, represent them as multiples of unknowns and form equations using the savings information.

  • Example: Incomes of A and B are in the ratio (3:4), expenditures are in the ratio (2:3), and both save ₹2,000. Find their incomes. Solution:

Let incomes be:

3x, 4x3x,\ 4x

Let expenditures be:

2y, 3y2y,\ 3y

Since both save ₹2,000:

3x2y=2000(1)3x-2y=2000 \tag{1} 4x3y=2000(2)4x-3y=2000 \tag{2}

Subtract (1) from (2):

xy=0x-y=0 x=yx=y

Substitute in (1):

3x2x=20003x-2x=2000 x=2000x=2000

Therefore incomes are:

6000, ₹8000\boxed{₹6000,\ ₹8000}

2. Income, Expenditure & Savings Percentage

  • Formula:
Savings=IncomeExpenditure \text{Savings}=\text{Income}-\text{Expenditure} \text{Savings%}=\frac{\text{Savings}}{\text{Income}}\times100 \text{Expenditure%}=100-\text{Savings%}
  • Example: A earns ₹40,000 and saves 25% of his income. Find his monthly expenditure. Solution:

Savings:

=25=25%\times40000=₹10000

Expenditure:

=4000010000=40000-10000 30000\boxed{₹30000}

3. Change in Income and Expenditure

  • Formula:
S=IE S=I-E

After changes:

S=I(1+x100)E(1+y100) S' = I\left(1+\frac{x}{100}\right) -E\left(1+\frac{y}{100}\right)

Use when income and expenditure change by different percentages.

  • Example: A person’s income is ₹30,000 and expenditure is ₹24,000. Income increases by 20% and expenditure by 10%. Find the percentage change in savings. Solution:

Original savings:

3000024000=600030000-24000=₹6000

New income:

30000(1.2)=3600030000(1.2)=₹36000

New expenditure:

24000(1.1)=2640024000(1.1)=₹26400

New savings:

3600026400=960036000-26400=₹9600

Increase in savings:

96006000=36009600-6000=₹3600

Percentage increase:

\frac{3600}{6000}\times100 =\boxed{60%}

4. Proportional Scaling

  • Formula:
a:b=c:dad=bc a:b=c:d\Rightarrow ad=bc

Fourth proportional:

a:b=c:xx=bca a:b=c:x \Rightarrow x=\frac{bc}{a}

Use for direct proportion and missing terms in ratios.

  • Example: Find the fourth proportional to 8, 12 and 18. Solution:
8:12=18:x8:12=18:x 8x=12×188x=12\times18 x=2168x=\frac{216}{8} 27\boxed{27}

5. Third Proportional

  • Formula: If:
a:b=b:x a:b=b:x

then:

x=b2a \boxed{x=\frac{b^2}{a}}
  • Example: Find the third proportional to 6 and 12. Solution:
6:12=12:x6:12=12:x 6x=1446x=144 x=24\boxed{x=24}

6. Mean Proportional

  • Formula: If (x) is the mean proportional between (a) and (b):
a:x=x:b a:x=x:b

Therefore:

x=ab \boxed{x=\sqrt{ab}}
  • Example: Find the mean proportional between 4 and 25. Solution:
x=4×25x=\sqrt{4\times25} x=100x=\sqrt{100} 10\boxed{10}

7. Direct Proportion

  • Formula:
yxy1x1=y2x2 y\propto x \Rightarrow \frac{y_1}{x_1}=\frac{y_2}{x_2}

Hence:

y2=y1x2x1 y_2=y_1\frac{x_2}{x_1}

Use when both quantities increase or decrease together in the same ratio.

  • Example: 5 pens cost ₹75. What is the cost of 8 pens? Solution:
755=x8\frac{75}{5}=\frac{x}{8} x=75×85x=75\times\frac85 120\boxed{₹120}

8. Inverse Proportion

  • Formula:
y1xx1y1=x2y2 y\propto\frac1x \Rightarrow x_1y_1=x_2y_2

Use when one quantity increases while the other decreases proportionally, such as workers and days.

  • Example: 8 workers complete a job in 15 days. How many days will 12 workers take, assuming equal efficiency? Solution:
8×15=12×d8\times15=12\times d d=12012d=\frac{120}{12} 10 days\boxed{10\text{ days}}

9. Chain Ratios

  • Formula: To combine:
A:B=x:y,B:C=p:q A:B=x:y,\qquad B:C=p:q

make the values of (B) equal by multiplying the ratios appropriately.

  • Example: If (A:B=3:4) and (B:C=5:6), find (A:B:C). Solution:
A:B=3:4A:B=3:4 B:C=5:6B:C=5:6

LCM of 4 and 5 is 20.

A:B=15:20A:B=15:20 B:C=20:24B:C=20:24

Therefore:

A:B:C=15:20:24\boxed{A:B:C=15:20:24}

10. Multiple Chain Ratios

  • Formula: Combine consecutive ratios by making every common term equal.
  • Example: If (A:B=2:3), (B:C=4:5), and (C:D=10:7), find (A:B:C:D). Solution:

First:

A:B=2:3,B:C=4:5A:B=2:3,\quad B:C=4:5

Make (B=12):

A:B=8:12A:B=8:12 B:C=12:15B:C=12:15

Thus:

A:B:C=8:12:15A:B:C=8:12:15

Now (C:D=10:7). Make (C=30):

A:B:C=16:24:30A:B:C=16:24:30 C:D=30:21C:D=30:21

Therefore:

A:B:C:D=16:24:30:21\boxed{A:B:C:D=16:24:30:21}

11. Ratio Division of a Quantity

  • Formula: If a quantity (Q) is divided in ratio:
a:b:c a:b:c

then:

Shares=aa+b+cQ, ba+b+cQ, ca+b+cQ \text{Shares}= \frac{a}{a+b+c}Q,\ \frac{b}{a+b+c}Q,\ \frac{c}{a+b+c}Q
  • Example: Divide ₹4,500 among A, B and C in the ratio (2:3:4). Solution:

Total parts:

2+3+4=92+3+4=9

A:

4500×29=10004500\times\frac29=\boxed{₹1000}

B:

4500×39=15004500\times\frac39=\boxed{₹1500}

C:

4500×49=20004500\times\frac49=\boxed{₹2000}

12. Ratio Change After Addition/Subtraction

  • Formula: If two quantities are in ratio (a:b), write them as:
ax, bx ax,\ bx

Then apply the given addition/subtraction and form the new ratio.

  • Example: Two numbers are in the ratio (3:5). If 8 is added to each, their ratio becomes (5:7). Find the numbers. Solution:

Let numbers be:

3x, 5x3x,\ 5x

After adding 8:

3x+85x+8=57\frac{3x+8}{5x+8}=\frac57 7(3x+8)=5(5x+8)7(3x+8)=5(5x+8) 21x+56=25x+4021x+56=25x+40 4x=164x=16 x=4x=4

Numbers:

12, 20\boxed{12,\ 20}

13. Compound Proportion

  • Formula: If a quantity depends directly on some variables and inversely on others:
QA×BC×D Q\propto \frac{A\times B}{C\times D}

Compare two situations using the corresponding ratios.

  • Example: 8 workers working 6 hours per day complete a job in 10 days. How many days will 12 workers working 8 hours per day take? Solution:

Work is constant:

8×6×10================12×8×d8\times6\times10 ================ 12\times8\times d d=8×6×1012×8d=\frac{8\times6\times10}{12\times8} d=5 days\boxed{d=5\text{ days}}

14. Partnership Ratios

  • Formula:
Profit shareCapital×Time \text{Profit share}\propto\text{Capital}\times\text{Time}

Therefore:

P1:P2=I1T1:I2T2 P_1:P_2=I_1T_1:I_2T_2
  • Example: A invests ₹5,000 for 12 months and B invests ₹8,000 for 9 months. Find their profit-sharing ratio. Solution:
A:B=(5000×12):(8000×9)A:B=(5000\times12):(8000\times9) =60000:72000=60000:72000 5:6\boxed{5:6}

15. Partnership with Change in Capital

  • Formula:
Profit ratio=I1T1:I2T2 \text{Profit ratio}=I_1T_1:I_2T_2

If capital changes during the year, divide the investment period into separate intervals and calculate:

Effective capital=(Capital×Time) \text{Effective capital} =\sum(\text{Capital}\times\text{Time})
  • Example: A invests ₹10,000 for 12 months. B invests ₹8,000 for 6 months and then increases it to ₹12,000 for the remaining 6 months. Find the profit ratio. Solution:

A’s effective investment:

10000×12=12000010000\times12=120000

B’s:

8000×6+12000×68000\times6+12000\times6 =48000+72000=120000=48000+72000=120000

Therefore:

A:B=1:1\boxed{A:B=1:1}

16. Dilution & Mixture Ratio

  • Formula: If a mixture contains two components in ratio (a:b):
Quantity of first:Quantity of second=a:b \text{Quantity of first}: \text{Quantity of second}=a:b

For replacement/dilution, track the amount of the original component remaining after each operation.

  • Example: A vessel contains milk and water in the ratio (3:1). If 20 L of the mixture is taken out and replaced with 20 L water, find the amount of milk removed when the vessel initially contains 80 L. Solution:

Initial milk:

80×34=60 L80\times\frac34=60\text{ L}

Milk fraction:

34\frac34

Milk removed:

20×34=15 L20\times\frac34=15\text{ L}

Milk remaining:

6015=45 L60-15=\boxed{45\text{ L}}

Advanced Variants

17. Ratio-Based Income, Expenditure & Savings

  • Formula: If:
IA:IB=a:b,EA:EB=c:d I_A:I_B=a:b,\qquad E_A:E_B=c:d

and savings are known, represent:

IA=ax, IB=bx,EA=cy, EB=dy I_A=ax,\ I_B=bx,\quad E_A=cy,\ E_B=dy

Then use:

IAEA=SA,IBEB=SB I_A-E_A=S_A,\qquad I_B-E_B=S_B
  • Example: Incomes of A and B are in ratio (4:5), expenditures in ratio (3:4), and their savings are ₹3,000 and ₹2,000 respectively. Find their incomes. Solution:

Let:

IA=4x,IB=5xI_A=4x,\quad I_B=5x EA=3y,EB=4yE_A=3y,\quad E_B=4y

Then:

4x3y=30004x-3y=3000 5x4y=20005x-4y=2000

Multiply first by 4:

16x12y=1200016x-12y=12000

Second by 3:

15x12y=600015x-12y=6000

Subtract:

x=6000x=6000

Therefore:

IA=4(6000)=24000I_A=4(6000)=\boxed{₹24000} IB=5(6000)=30000I_B=5(6000)=\boxed{₹30000}

18. Continued Proportion

  • Formula: If:
a:b=b:c a:b=b:c

then:

b2=ac b^2=ac

This is useful for identifying geometric-progressive relationships.

  • Example: Find (x) if (4:x=x:25). Solution:
x2=4×25x^2=4\times25 x2=100x^2=100

For a positive quantity:

x=10\boxed{x=10}

19. Componendo and Dividendo

  • Formula: If:
ab=cd \frac ab=\frac cd

then:

a+bab===============c+dcd \frac{a+b}{a-b} =============== \frac{c+d}{c-d}

Use to simplify ratio equations involving sums and differences.

  • Example: If (a:b=3:2), find ((a+b):(a-b)). Solution:

Let:

a=3x,b=2xa=3x,\quad b=2x

Then:

a+b=5xa+b=5x ab=xa-b=x

Therefore:

(a+b):(ab)=5:1\boxed{(a+b):(a-b)=5:1}

20. Direct and Inverse Proportion Combined

  • Formula:
QA×BC Q\propto\frac{A\times B}{C}

Therefore:

Q1Q2===============A1A2×B1B2×C2C1 \frac{Q_1}{Q_2} =============== \frac{A_1}{A_2} \times \frac{B_1}{B_2} \times \frac{C_2}{C_1}
  • Example: The time required for a job is directly proportional to the amount of work and inversely proportional to the number of workers. If work doubles and workers increase by 50%, how does the time change? Solution:
TWMT\propto\frac{W}{M}

Thus:

T2T1===============21×11.5\frac{T_2}{T_1} =============== \frac{2}{1}\times\frac{1}{1.5} =43=\frac43

Therefore time becomes:

43 times the original\boxed{\frac43\text{ times the original}}

or a:

\boxed{33\frac13%\text{ increase}}

My Private Notes

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