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HCF Concepts
QUANTITATIVEAPTITUDE

HCF Concepts

Learn highest common factor methods and applications in number-system aptitude problems.

1. HCF of Numbers

  • Idea: Finding the greatest number that divides two or more numbers exactly.

  • Formula:

HCF=Greatest common factor\text{HCF} = \text{Greatest common factor}
  • Example: Find the HCF of 36, 48 and 60.

    Solution:

    36 = 2² × 3²
    48 = 2⁴ × 3
    60 = 2² × 3 × 5

    Common factors:

22×3=12 2^2\times3=12

Answer: 12


2. Greatest Measure / Largest Size

  • Idea: Finding the largest length, capacity or size that can exactly measure or divide several given quantities.

  • Formula:

Greatest measure=HCF of the given quantities\text{Greatest measure}=\text{HCF of the given quantities}
  • Example: Find the largest rod that can measure 42 m, 63 m and 84 m exactly.

    Solution:

HCF(42,63,84)=21 HCF(42,63,84)=21

Answer: 21 m


3. Maximum Equal Groups

  • Idea: Dividing different quantities into equal groups of the largest possible size.

  • Formula:

Maximum group size=HCF of the quantities\text{Maximum group size}=\text{HCF of the quantities}
  • Example: Three stacks contain 96, 144 and 240 books. Find the largest possible number of books in each equal pile.

    Solution:

HCF(96,144,240)=48 HCF(96,144,240)=48

Answer: 48 books per pile


4. Greatest Number Leaving the Same Remainder

  • Idea: Finding the greatest number that divides several numbers and leaves the same remainder.

  • Formula:

Required number======================HCF(ar,br,cr)\text{Required number} ====================== HCF(a-r,b-r,c-r)
  • Example: Find the greatest number that divides 867 and 255, leaving remainder 3 in each case.

    Solution:

8673=864 867-3=864 2553=252 255-3=252

Therefore,

HCF(864,252)=36 HCF(864,252)=36

Answer: 36


5. Greatest Number Leaving Different Remainders

  • Idea: Finding the greatest number that leaves different specified remainders.

  • Formula:

Required number======================HCF(ar1,br2,cr3)\text{Required number} ====================== HCF(a-r_1,b-r_2,c-r_3)
  • Example: Find the greatest number that divides 65, 89 and 113 leaving remainders 2, 5 and 8 respectively.

    Solution:

652=63 65-2=63 895=84 89-5=84 1138=105 113-8=105

Therefore,

HCF(63,84,105)=21 HCF(63,84,105)=21

Answer: 21


6. HCF of Fractions

  • Idea: Finding the HCF when the given numbers are fractions.

  • Formula:

HCF(ab,cd)=================================HCF(a,c)LCM(b,d)HCF\left(\frac ab,\frac cd\right) ================================= \frac{HCF(a,c)}{LCM(b,d)}
  • Example: Find the HCF of
512,718\frac{5}{12},\frac{7}{18}

Solution:

HCF(5,7)=1HCF(5,7)=1 LCM(12,18)=36LCM(12,18)=36

Therefore,

HCF=136HCF=\frac1{36}

Answer: (\frac1{36})


7. HCF of Decimals

  • Idea: Removing decimal places and finding the HCF of the resulting integers.

  • Formula:

    Multiply all numbers by the same power of 10 until they become integers.

  • Example: Find the HCF of 1.2, 1.8 and 2.4.

    Solution:

    Multiply all by 10:

    1.2 → 12
    1.8 → 18
    2.4 → 24
HCF(12,18,24)=6 HCF(12,18,24)=6

Divide by 10:

HCF=0.6 HCF=0.6

Answer: 0.6


8. HCF Using Euclidean Algorithm

  • Idea: Quickly finding the HCF of large numbers using repeated division.

  • Formula:

HCF(a,b)=HCF(b,amodb)HCF(a,b)=HCF(b,a\bmod b)
  • Example: Find the HCF of 867 and 255.

    Solution:

    867 = 255 × 3 + 102
    255 = 102 × 2 + 51
    102 = 51 × 2 + 0

    Therefore:

HCF=51 HCF=51

Answer: 51


Advanced

9. HCF of Algebraic Expressions

  • Idea: Finding the common factor of algebraic expressions.

  • Formula:

    Factorise each expression and take the common factors with the smallest powers.

  • Example: Find the HCF of

x29x^2-9

and

x26x+9x^2-6x+9

Solution:

x29=(x3)(x+3)x^2-9=(x-3)(x+3) x26x+9=(x3)2x^2-6x+9=(x-3)^2

Common factor:

x3x-3

Answer: (x-3)


10. HCF–LCM Relationship

  • Idea: Finding one of HCF or LCM when the other and the numbers are known.

  • Formula:

HCF(a,b)×LCM(a,b)=a×bHCF(a,b)\times LCM(a,b)=a\times b
  • Example: The HCF of two numbers is 12 and their LCM is 180. If one number is 36, find the other.

    Solution:

12×180=36×x 12\times180=36\times x x=216036=60 x=\frac{2160}{36}=60

Answer: 60

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